What this quiz covers
Grade 12 Finance Growth and Decay - Question 7 draws its questions at random from a bank of 15 questions, with full worked solutions for every one.
Worked examples
A few of the question types, with full solutions, so you know what to expect.
Which formula correctly converts Sarah's nominal rate to an effective annual rate?
- \(1+i_{\text{eff}}=\left(1+\frac{0.11}{2}\right)^2\)
- \(i_{\text{eff}}=\frac{0.11}{2}\)
- \(1+i_{\text{eff}}=\left(1+0.11\right)^2\)
- \(1+i_{\text{eff}}=1+0.11\times2\)
Answer: \(1+i_{\text{eff}}=\left(1+\frac{0.11}{2}\right)^2\)
Compounded semi-annually means interest is compounded \(2\) times per year.
Use \(1+i_{\text{eff}}=\left(1+\frac{i}{m}\right)^m\).
What is Sarah's effective annual interest rate to two decimal places?
- \(11{,}30\%\)
- \(11{,}42\%\)
- \(5{,}50\%\)
- \(11{,}00\%\)
Answer: \(11{,}30\%\)
\(i_{\text{eff}}=\left(1+\frac{0.11}{2}\right)^2-1\).
\(i_{\text{eff}}=0.113025\ldots=11.3025\ldots\%\).
Whose investment earns the higher rate per annum?
- Mary's investment, because \(11{,}42\%>11{,}30\%\).
- Sarah's investment, because \(11\%\) is compounded twice.
- They are equal after converting Sarah's rate.
- Sarah's investment, because \(11{,}30\%>11{,}42\%\).
Answer: Mary's investment, because \(11{,}42\%>11{,}30\%\).
The comparison must use Sarah's effective rate, not only her nominal rate.
\(11{,}42\%\) is greater than \(11{,}30\%\).
How many monthly deposits are made?
- \(114\)
- \(113\)
- \(108\)
- \(120\)
Answer: \(114\)
From 1 November 2016 to 1 October 2025 gives \(9\times12=108\) payments.
From 1 November 2025 to 1 April 2026 gives \(6\) more payments.
Which monthly interest rate should be used in the annuity calculation?
- \(i=\frac{0.0772}{12}\)
- \(i=0.0772\times12\)
- \(i=\frac{7.72}{12}\)
- \(i=\frac{0.772}{12}\)
Answer: \(i=\frac{0.0772}{12}\)
Convert \(7{,}72\%\) to decimal form: \(0.0772\).
Because interest is compounded monthly, divide the annual nominal rate by \(12\).