Grade 11 Ungrouped Data Quiz 1 draws its questions at random from 16 questions across these topics:
A few of the question types, with full solutions, so you know what to expect.
Central Tendency. Calculate the mean of the data set: 12, 8, 15, 5, 10.
Answer: 10
Add every value: \( 12 + 8 + 15 + 5 + 10 = 50 \).
Divide by the number of values \( (n = 5) \): \( \bar{x} = \dfrac{50}{5} \).
Central Tendency. Find the median of: 3, 9, 4, 7, 6.
Answer: 6
First put the data in order: 3, 4, 6, 7, 9.
There are \( n = 5 \) values (odd), so the median is the middle (3rd) value.
Central Tendency. Find the median of: 10, 4, 8, 6, 12, 2.
Answer: 7
Order the data: 2, 4, 6, 8, 10, 12.
There are \( n = 6 \) values (even), so average the two middle values (3rd and 4th):
\( \text{median} = \dfrac{6 + 8}{2} = \dfrac{14}{2} \)
Central Tendency. What is the mode of: 4, 7, 4, 9, 4, 7, 2?
Answer: 4
The mode is the value that appears most often.
Count them: 4 appears three times, 7 appears twice, and 2 and 9 once each.
Dispersion - Range. Calculate the range of: 23, 11, 45, 30, 18.
Answer: 34
Range = maximum value - minimum value.
Maximum \( = 45 \), minimum \( = 11 \).
\( \text{Range} = 45 - 11 \)