Topic: Angles of Triangles  ·  Grade: 8
Questions: 8  ·  Skills: Angle sum · Isosceles · Exterior angle theorem

What this quiz covers

Grade 8 Angles of Triangles Quiz 1 draws its questions at random from 8 questions across these topics:


Worked examples

A few of the question types, with full solutions, so you know what to expect.

Angle Sum of a Triangle. In triangle ABC, the interior angles are \((4x + 10)°\), \((5x + 5)°\) and \(2x°\). What is the value of \(x\)?

  1. \(x = 12°\)
  2. \(x = 15°\)
  3. \(x = 18°\)
  4. \(x = 20°\)

Answer: \(x = 15°\)

The angles of a triangle sum to 180°.

\((4x+10) + (5x+5) + 2x = 180\)

\(11x + 15 = 180\)

\(11x = 165\)

\(x = 15°\)

The angles are: \(4(15)+10 = 70°\), \(5(15)+5 = 80°\), \(2(15) = 30°\).

Classifying Triangles — Isosceles. Triangle DEF has DE = DF (indicated by tick marks) and EF = 10 cm. What type of triangle is DEF?

  1. Scalene triangle
  2. Isosceles triangle
  3. Equilateral triangle
  4. Right-angled triangle

Answer: Isosceles triangle

The tick marks show DE = DF — two sides of the triangle are equal in length.

A triangle with exactly two equal sides is called an isosceles triangle.

Property: the base angles of an isosceles triangle are equal, so ∠DEF = ∠DFE.

Angle Sum — Isosceles Triangle. In triangle GHJ, ∠G = 22° and ∠J = 22°. What is the size of angle H?

  1. 126°
  2. 131°
  3. 136°
  4. 141°

Answer: 136°

Since ∠G = ∠J = 22°, the sides opposite these angles are equal (HJ = GH = 7 cm).

This means triangle GHJ is isosceles.

Using the angle sum of a triangle:

\(\angle H = 180° - \angle G - \angle J = 180° - 22° - 22°\)

\(\angle H = 136°\)

Exterior Angle Theorem. Points J, K, L, M lie on a straight line. Using the exterior angle theorem, what is the value of \(x\)?

  1. 55°
  2. 60°
  3. 65°
  4. 70°

Answer: 70°

The exterior angle of a triangle equals the sum of the two non-adjacent interior angles.

∠NLM is an exterior angle of triangle KLN:

\((2x - 30) = (2x - 80) + (x - 20)\)

\(2x - 30 = 3x - 100\)

\(70 = x\)

Check at K (angles on a straight line): \((2y-10)+(2x-80)=180°\) → \(y = 65°\).

Angles in a Right Triangle. AD ⊥ BC so ∠ADB = 90°. Given ∠B = 41°, what is the value of angle \(y\) (i.e. ∠BAD)?

  1. 39°
  2. 44°
  3. 49°
  4. 54°

Answer: 49°

In triangle ABD: ∠B + ∠ADB + ∠BAD = 180°

\(41° + 90° + y = 180°\)

\(131° + y = 180°\)

\(y = 49°\)